Which statement is always true about the graph of an equation in the form y=kx? a)the point (0,k) is on the graph. b)the point (1,1) is on the graph. c)the point (k,0) is on the graph d)the point (0,0) is on the graph.

d)The point (0,0) is on the graph.

Step-by-step explanation:

Select statement is always true about the graph of an equation in the form y=kx

(0,k)  , x=0  and y=k

LEts plug in x=0 in y= kx

y=k(0) =0, so the point (0,k) on the graph of y=kx is not true

(1,1)  , x=1  and y=1

LEts plug in x=1 in y= kx

y=k(1) =k, so the point (1,1) on the graph of y=kx is not true

(k,0)  , x=k  and y=0

LEts plug in x=k  in y= kx

y=k(k) =k^2, so the point (k,0) on the graph of y=kx is not true

(0,0)  , x=0  and y=0

Lets plug in x=0 in y= kx

y=k(0) =0, so the point (0,0) on the graph of y=kx is true

2 over 5

step-by-step explanation:

the 2: 3 ratio is the length of the ac segment to the cb segment total length. this implies that the ratio between segment ac length and segment ab length is 2: 5. point c is 2/5 from a to b, so the required fraction is 2/5.