Atriangle has vertices (-1, 2), (3, 1), and (7, 2). what is the approximate perimeter of the triangle? round your answer to the nearest hundredth.

AB = √[ (1 – 2)^2 + (3 - (-3) )^2 ] = √[ (-1)^2 + (6)^2 ] = √[ 1 + 36 ] = √(37) units

BC = √[ (2 - (-1) )^2 + (-3 - (-1))^2 ] = √[ (3)^2 + (-2)^2 ] = √[ 9 + 4 ] = √(13) units

AC = √[ (-1 – 1)^2 + (-1 – 3)^2 ] = √[ (-2)^2 + (-4)^2 ] = √[ 4 + 16 ] = √(20) units

AB +BC +AC = √(37) + √(13) + √(20) units

Therefore, the perimeter of this triangle will be √(37) + √(13) + √(20) units

I hope this helps!

Adios!:)

mark brainliest

step-by-step explanation:

2 tens + 6 ones

1 ten + 16 ones

0 tens + 26 ones

what is the graph

step-by-step explanation: