If xy + 2ey = 2e, find the value of y'' at the point where x = 0.

y = 1 is the value at x = 0

Step-by-step explanation:

The given equation is xy + 2ey = 2e

We have to solve this equation to find the value of y at the point x = 0.

xy + 2ey = 2e

y(x + 2e) = 2e

Now we divide this equation by (x + 2e) on both the sides of the equation.

Now we have find the value of y at x = 0

By putting x = 0 in the simplified form of the equation

So the value of y is 1.

answer: yes, he is correct

step-by-step explanation: 10x-1=59

                                              1-1=0     59+1=60

60/10=x=6

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: