Which equation results from applying the secant and tangent segment theorem to the figure? 12(a + 12) = 10^2 10 + 12 = a^2 10(a + 10) = 12^2 10(12) = a^2

The equation that results from applying the secant and tangent segment theorem to the figure is 12²  = 10(a+10)

According to the secant and tangent segment theorem, the square of the tangent line is equal to the product of the secant segments. Mathematically;

Tangent² = whole secant segment × External secant segment

DE² = AD × BD

Given

DE = 12

AD = a+10

BD = 10

Substitute into the formula:

12²  = 10(a+10)

Hence the equation that results from applying the secant and tangent segment theorem to the figure is 12²  = 10(a+10)

learn more on secant and tangent segment theorem here: link

a

step-by-step explanation:

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844