Mathematics, 16.10.2019 17:30 jcduarte

Im stuck needed

1. the leg of a right triangle is 3 units and the hypotenuse is 11 units. what is the length, in units, of the other leg of the triangle?
112 units
square root 112 units
130 units
square root 130 units

the sets of numbers 3, 4, 5 and 8, 15, 17 are pythagorean triples. use what you know about the pythagorean theorem and explain or show why they are pythagorean triples. be sure to show your work for each set of triples! i don’t know what to write

the legs of a right triangle are 6 units and 7 units. what is the length of the hypotenuse?

square root 13 units
13 units
square root 85 units
85 units

Im stuck needed 1. the leg of a right triangle is 3 units and the hypotenuse is 11 uni

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Answer from: karenjunior

1. The measure of other leg is √(112) units. Therefore the correct option is 2.

2. The sets of numbers 3, 4, 5 and 8, 15, 17 are Pythagorean triples.

3. Therefore, the length of the hypotenuse is√(85).

4. Frank walks 19.31 blocks.

Step-by-step explanation:

1. The leg of a right triangle is 3 units and the hypotenuse is 11 units.

Using Pythagoras theorem:

(hypotenuse)^2=(leg_1)^2+(leg_2)^2

(11)^2=(3)^2+(leg_2)^2

121=9+(leg_2)^2

121-9=(leg_2)^2

112=(leg_2)^2

Taking square root both the sides.

$\sqrt{112}=leg_2$

The measure of other leg is √(112) units. Therefore the correct option is 2.

2. According to the Pythagorean Theorem, the sum of squares of two legs of a right angled triangle is equal to the sum of square of its hypotenuse.

(hypotenuse)^2=(leg_1)^2+(leg_2)^2

The set of numbers is called Pythagorean triples if the sum of squares of two small numbers equal to the square of larger number.

Check the set 3,4,5.

(5)^2=(3)^2+(4)^2

25=9+16

25=25

LHS=RHS, therefore the the set 3,4,5 is a Pythagorean triples.

Check the set 8,15,17.

(17)^2=(8)^2+(15)^2

289=64+225

289=289

LHS=RHS, therefore the the set 8,15,17 is a Pythagorean triples.

The legs of a right triangle are 6 units and 7 units.

Using Pythagorean Theorem,

(hypotenuse)^2=(leg_1)^2+(leg_2)^2

(hypotenuse)^2=(6)^2+(7)^2

(hypotenuse)^2=36+49

(hypotenuse)^2=85

Taking square root both the sides.

$hypotenuse=\sqrt{85}$

Therefore, the length of the hypotenuse is√(85).

4. From the given figure it is clear that the distance between Derek's and Evan's house is 8 blocks. The distance between Frank's and Evan's house is 8 blocks.

Using Pythagoras theorem the distance between Derek's and Frank's house is

(hypotenuse)^2=(leg_1)^2+(leg_2)^2

(hypotenuse)^2=(8)^2+(8)^2

(hypotenuse)^2=64+64

Taking square root both the sides.

$(hypotenuse)=\sqrt{128}=11.31$

The distance between Derek's and Frank's house is 11.31 blocks.

It is given that frank walk from his house to derek's house, then on to Evan's house along the path shown. So the total distance covered by him is

D=11.31+8=19.31

Therefore Frank walks 19.31 blocks.

Answer from: Quest

21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.

Answer from: Quest

What the proper work

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