Pls me asap yuri surveyed randomly selected middle school students in his neighborhood. he found that around 60% of them plan to participate in a charity walk organized by the town council. what is the estimated probability that it will take at least six middle school students to find one who doesn't plan to participate in the charity walk? use the table of simulated values to answer the question. the numbers 0 to 5 represent middle school students planning to participate in the charity walk, and 6 to 9 represent those who are not planning to participate. 71078 88530 30057 38546 56642 93077 92544 54028 48398 40081 44414 70273 89398 52476 76171 93472 45432 26626 38532 75962 95427 15711 88441 10204 50516 51306 83316 20695 31542 62569 70849 58001 66224 81879 44877 96787 28608 10468 18317 22426 60702 36430 18257 55518 38977 56725 84351 78605 61936 31105 a.0.02 b.0.10 c.0.30 d.0.60

C. 0.30

Step-by-step explanation:

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )