Two boys are throwing a baseball back and forth. the ball is 4 ft above the ground when it leaves one child’s hand with an upward velocity of 36 ft/s. if acceleration due to gravity is –16 ft/s2, how high above the ground is the ball 2 s after it is thrown?

Step-by-step explanation:

It is given that, two boys are throwing a baseball back and forth.

Height above ground, h₀ = 4 ft

Initial velocity of child, u = 36 ft/s

Acceleration due to gravity, a = -16 ft/s²

The equation of projectile motion is given by :

According to the given condition,  

h(t) = 2.356 meters

Height of the ball at t = 2 s

h = 12 ft

So, at t = 2 seconds the height of the ball is 12 feet from the ground. Hence, this is the required solution.

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation:

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.