Aship is 15 miles due west of lighthouse a on the island of hawaii. if lighthouse b is 6.2 miles due south of lighthouse a, what is the bearing to the nearest tenth of a degree of the ship from lighthouse b? to the nearest tenth of a mile, how far is the ship from lighthouse b?

67.5°

16.2 miles

Step-by-step explanation:

According to data, ship is at 15 miles due west to light house A.

Light house B is 6.2 miles due south of Light house A

Now,

                Ship15 milesLight house A

                                                            ║

                                                            ║ 6.2 miles

                                                            ║  

                                                            Light house B

You can see that, if you draw an imaginary straight line from light house B to ship, it is forming a right angle triangle,

so, according to Pythagoras theorem,

(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2

We need to find hypotenuse,

Base = 6.2, Perpendicular = 15

So, H^2 = (15)^2 + (6.2)^2

H^2 = 225 + 38.44

H = 16.23 miles

now for rounding of to nearest 10th place

H = 16.2 miles

Now for angle of Ship from light house is

Cos^Ф = Base/Hypotenuse

Base = 6.2

Hypotenuse = 16.2

Cos^Ф = 6.2/16.2

Ф = 67.49°

After rounding off to the nearest tenth place

Ф = 67.5°

y > 1/3x

y < = -x + 4

hope this : )

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116