Where does the graph of y = sin x from x = 0 to x = 2π start? a. at its minimum b. at an x-intercept c. at its maximum d. between an x-intercept and its maximum

The graph of y=sin x start from x-intercept.

B is correct.

Step-by-step explanation:

Given:

From

We need to find starting point of graph.

Graph will start when x=0

Put x = 0 into y = sin x

We get,

y = sin (0)

y = 0

Starting point is (0,0)

The value of y is 0.

It would be x-intercept of graph.

Hence, The graph of y=sin x start from x-intercept.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

answer: both chords and diameters have two endpoints on a circle. diameters must intersect the center of a circle.