Apublisher displays its latest magazine cover on its website. the publisher scales up the front cover of the magazine using a scale of 6 centimeters to 1 inch. the length of the scale drawing is 48 centimeters, and its width is 66 centimeters. the length of the actual magazine cover is inches. the width of the actual magazine cover is inches. the scale drawing is too big to view on a computer screen without scrolling. so, the publisher uses a new scale of 4 centimeters to 1 inch. the length of the new scale drawing is centimeters. the width of the new scale drawing is centimeters. me with this question.

1). Length = 8 and width = 11 cm

2). Width = 44 cm

Step-by-step explanation:

A publisher scales up the front cover of the magazine using a scale of 6 cm to 1 inch.

Since the length and width of the scale drawing are 48 cm. and 66 cm.

By the scale factor we have to find the scaled length of the cover.

∵ 6 cm length of the cover = 1 inch

∴ 1 cm length of the cover = inch

∴ 48 cm length of the cover = inch

                                               = 8 inches

Similarly scaled width of the cover = = 11 inches

Since width of the magazine cover was too big to view on computer.

So new scale 4 cm to inch was used.

By this scale factor we have to find the scaled width of the drawing.

∵ 1 inch width of the drawing = 4 cm

∴ 11 inch width of the drawing = 11×4

                                                    = 44 cm.

jhfdergmllm: $"$& (& #@$& () 9887¥€¢£`~¥°℅™℅℅℅=

step-by-step explanation:

π^°×{{€€

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl