Assume the random variable x is normally distributed with mean mu equals 50μ=50 and standard deviation sigma equals 7σ=7. compute the probability. be sure to draw a normal curve with the area corresponding to the probability shaded. upper p left parenthesis upper x greater than 41 right parenthesisp(x> 41) which of the follow

P(X>41) = 0.9015 or 90.15%

Step-by-step explanation:

We have a mean and a standard deviation .

To answer the probability P(X>41), or the probability that in a Normal Distribution, with mean and standard deviation , we have values greater than 41.

We use here values for the standardized normal curve, for which, we know that the z variable describes a Normal Distribution with mean and standard deviation .

Having

The value z = 1.2857 corresponds to a cumulative probability of 0.4015 (approximately). But we are interested in z = -1.2857.

Since the Normal Distribution is symmetrical, the z-score of 0.4015 indicates the distance from the population mean (the value is 0.4015 units from the mean).

Then, we have to subtract that value from the mean for the z-score value z = -1.2857 (the value is below the mean, denoted by the minus sign). So, the cumulative probability for the latter z-score is 0.5000-0.4015=0.0985. This is the cumulative probability for P(x<41).

Well, the cumulative probability for P(x>41) is 1 - 0.0985 = 0.9015 or 90.15%. The graph below represents this cumulative probability (dark violet area).

step-by-step explanation:

compare

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic