Diagram shows an irregular hexagon pqrstu. fine the value of x + y=

To find the value of x+y, we will first find the sum of all the interior angles of the hexagon.The sum of the interior angles in a hexagon is always equal to 720 degrees.

All the angles in the diagram are in terms of x or y except for angle t. However, we know that the corresponding exterior angle is 30 degrees. The sum of angle t and 30 is 360. We can solve this in an algebraic equation.

t+30=360
Subtract 30 from both sides
t = 330

Now, we can solve for the values of x+y. We can set this up in another algebraic equation.

x+x+x+2y+y+30=720

Combine like terms:
3x+3y+30 = 720

Subtract 30 from both sides:
3x+3y = 690

Divide both sides by 3:

x+y = 230

The sum of x and y is 230.

Set square i think so