For δabc, ∠a = x - 2, ∠b = x + 2, and ∠c = 2x - 20. if δabc undergoes a dilation by a scale factor of 2 to create δa'b'c' with ∠a' = 98 - x, ∠b' = x 2 + 27, and ∠c' = x + 30, which confirms that δabc∼δa'b'c by the aa criterion?

a = ∠a' = 48° and ∠c = ∠c' = 80°

step-by-step explanation:

∠a = ∠a' = 48° and ∠c = ∠c' = 80°

x - 2 + x + 2 + 2x - 20 = 180

4x - 20 = 180

4x = 200

x = 50

then, plug in x to find angle measurements.

by the aa criterion, if two of the angles of a triangle are congruent the triangles are similar.

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°