What is the slant height of a square pyramid that has a surface area of 279 square meters and a side length of 9 meters?

l = 11 meters

Step-by-step explanation:

Surface area = s² + 2s*l

Where "l" is the slant height

Given: Surface area = 279 ; side length s = 9

Now plug in these values in the above formula, we get

279 = 9^2 + 2*9*l

279 = 81 + 18*l

18l = 279 - 81

18l = 198

Dividing both sides by 18, we get

l = 198/18

l = 11 meters

Therefore, slant height of the square pyramid = 11 meters

Hope this will helpful.

Thank you.

marco saved more.   he saved $35 more.

step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is