Agrocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. if peanuts cost $4.00 per pound and cashews cost $6.50 per pound, how many pounds of each should he use? let p = pounds of peanuts and let c = pounds of cashews. write a system of equations that could be used to solve the problem.

The required system of equations is,

p + c = 10

4.00p + 6.50c = 47.5

Step-by-step explanation:

Here p represents pounds of peanuts and c represents pounds of cashews,

Given,

Total pounds = 10,

⇒ p + c = 10,

Also, the total pounds is sold at the rate of $4.75 per pound,

So, the total expenditure = 4.75 × 10 = $ 47.5

Peanuts cost $4.00 per pound and cashews cost $6.50 per pound,

Total expenditure = ( 4.00p + 6.50c ) dollars,

⇒ 4.00p + 6.50c = 47.5

21.4 i did it already for s1

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0