The equation of a circle is (x + 12)2 + (y + 16)2 = (r1)2, and the circle passes through the origin. the equation of the circle then changes to (x – 30)2 + (y – 16)2 = (r2)2, and the circle still passes through the origin. what are the values of r1 and r2? a. r1 = 10 and r2 = 17 b. r1 = 10 and r2 = 34 c. r1 = 20 and r2 = 17 d. r1 = 20 and r2 = 34

Option D is correct

Step-by-step explanation:

Given Equations of Circles:

Circle 1 -

Circle 2 -  

Both circles passes through origin.

To find: Values of

Coordinates of origin = ( 0 , 0 )

Circles passes through origin means x = 0 & y = 0 must satisfy the equation of circles.

So, Substituting x = 0 &  y = 0 in Eqn of Circle 1

we get

Now, Substituting x = 0 &  y = 0 in Eqn of Circle 2

we get

Therefore, Option D is correct .i.e.,

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

the train arrives at 20: 27 hope i