The school that mofor gose to is selling tickets to the annual dance competition. on the first day of tickets sales the school sold 1 senior citizen ticket and 4 child tickets for a total of $57. the school took in $203 on the second day by selling 4 adult tickets. what is the price each of one adult ticket and one student ticket?

We will represent adults as x and students as y. Each adult ticket was $5 and each student ticket was $3, so we can write the equation as 5x + 3y = 460 We also know that the total number of tickets sold between the students and adults was 120. A second equation we make because of that is  x + y = 120 Now we have to ways to represent x and y and we need to use one to solve the other. I am going to rearrange the second equation to get y by itself.  y = 120 - x Now we plug this equation in for y in the top equation so 5x + 3y = 460 becomes 5x + 3(120 - x) = 460  then we distribute 5x + 360 - 3x = 460  combine like factors 2x + 360 = 460 2x =100x = 50 So we sold 50 adult tickets (x) and since there were 120 tickets sold total we know that we sold 70 student tickets Then we double check our math. 50 adult tickets x $5 each is $250  70 student tickets x $3 each = $210 $210 + $250 = $460  50 adult tickets and 70 student tickets

Think of it as five or above give it a shove. change the 5 or above to the right to a zero and add one to the number on the left.