One number is bigger than another by 406. if the bigger number is divided by the smaller one, you’ll get the quotient 3 and remainder 66. find the numbers.

The larger number is 576, the smaller number is 170.

Let x = the larger number and y = the smaller number.

We know that the larger number is 406 larger than the smaller one; therefore
x = y + 406

We also know


Substituting for x we have:


When we convert mixed numbers to improper fractions, we multiply the whole number by the denominator and add the numerator:


Since the denominators are the same, we can just set the numerators equal
y+406=3y+66

We cannot have a variable on both sides, so we will subtract y from both sides:
y+406-y=3y+66-y
406=2y+66

Subtract 66 from both sides:
406-66=2y+66-66
340=2y

Divide both sides by 2:
340/2 = 2y/2
170=y

The smaller number is 170.  Since the larger number is 406 larger, then it is 170+406=576.

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Answer: b 2 = 1.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

therefore, b 2= 1.