In the given figure, we have two right angled triangles:
1) Triangle ABC
2) Triangle CDB
Using pythagorean theorem, we can write equations for both triangles.
For triangle ABC:
![(15+x)^{2}= 17^{2}+ y^{2}](/tpl/images/0445/5483/9c8cb.png)
For triangle CDB:
![y^{2}= 8^{2}+ x^{2}](/tpl/images/0445/5483/e85cd.png)
Using the value of y² in the first equation, we get:
![(15+x)^{2}= 289 + 64 + x^{2} \\ \\ 225+30x+ x^{2} =353 + x^{2} \\ \\ 30x=128 \\ \\ x= \frac{128}{30} \\ \\ x= \frac{64}{15} ](/tpl/images/0445/5483/fb8bf.png)
![y^{2}= 8^{2}+ x^{2} \\ \\ y^{2}=64+ ( \frac{64}{15} )^{2} \\ \\ y^{2}= \frac{18496}{25} \\ \\ y= \frac{136}{15}](/tpl/images/0445/5483/cc2c9.png)
Thus the d option gives the correct values of x and yÂ