Acircular path 2feet wide has an inner diameter of 150 feet . how much farther is it around the outer edge of the path than around the inner edge?

12.56 feet

Step-by-step explanation:

Given: The width of the circular path= 2 feet

The inner diameter of circular path= 150 feet

Therefore, the inner radius of circular path=

Now, the outer radius= 75+2=77 feet

We know that the circumference=

Inner circumference=

Outer circumference=

The difference=

Hence, the outer edge of the path is 12.56 feet farther than the inner edge

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05