The numerator and denominator of a fraction are in the ratio of 3 to 5. if the numerator and denominator are both decreased by 2, the fraction is now equal to . if n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem? 5n = 3d and n - 2 = 2d - 4 5n = 3d and 2n - 4 = d - 2 3n = 5d and 2n - 4 = d - 2

You probably missed that when the numerator and denominator are both decreased by 2, the new fraction is now equal to 1/2.

The numerator of the fraction is "n" and the denominator of the fractions is "d". Initially the numerator and denominator are in the ratio 3 to 5. In equation form we can state this as:



When both numerator and denominator are decreased by 2, the new numerator will be n-2 and denominator will be d-2. These numerator and denominators are in ratio 1 to 2. In equation form we can write this as:



This is our second equation. Thus the two equation which can be used to solve the problem are:

5n = 3d
and
2n - 4 = d - 2

A5 miles because when you look at the chart count how many times it goes into it i don’t even know wha,t i’m saying anymore mpbut long stor6 short it’s 5 miles