Aslow jogger runs a mile in 13 min. calculate speed in. a) in/s b) km/h
(1mi=1609m); (1in=2.54),

a) 81.23 in per second  ,  b) 7.44 km / hour.

Step-by-step explanation:

Given: a slow jogger runs a mile in 13 min.

To find: Calculate speed in. a) in/s b) Km/h

Solution : We have given that jogger runs  1 mile = 13 min.

We know that  1 mile = 63360 inches

i minute = 60 second

Then Speed =  

Then Speed =  

a ) In inches / second

Plug   1 mile = 63360 inches

13 mint = 780 second

Speed =  

Speed = 81.23 in per second .

b) For km/h

Given 1 mile = 1609 m

1 kilometer =  1000 meter

1 mile = 1.609 km

1 hour = 60 mint

1 mint = 1/60

13 mint = .

13 mint= 0.216 hour

Then Speed = Speed =  

Speed = 7.44 km / hour.

Therefore, a) 81.23 in per second  ,  b) 7.44 km / hour.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

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