Fan for everyone who , medal for whoever the most! : ) 1. what is the sum of the polynomials? (m + n + 3) + (m + n + 4) 2. which expression can be used to find the difference of the polynomials? (10m – 6) – (7m – 4) 3. which expression can be used to find the difference of the polynomials? (4m – 5) – (6m – 7 + 2n),

1- The sum is: 2m + 2n + 7 = 2(m+n) + 7

2- The difference is: 3m - 2

3- The difference is: -2m - 2n + 2 = -2(m+n-1)

Explanation:

Before we begin, remember the following:

+ve * +ve = +ve

-ve * -ve = -ve

+ve * -ve = -ve

-ve * +ve = -ve

Also, remember that, we only add/subtract like terms. There are terms which have the same variable(s) raised to the same degree

Now, let's check the problems:

Problem 1:

Adding two polynomials:

(m + n + 3) + (m + n + 4)

We first start by getting rid of the brackets:

m + n + 3 + m + n + 4

Now, we add like terms:

2m + 2n + 7

As an additional step, we can take 2 as a common factor from the first two terms:

2(m+n) + 7

Problem 2:

Subtracting two polynomials:

(10m - 6) - (7m - 4)

We first start by getting rid of the brackets. Take care of the different signs while doing so:

10m - 6 - 7m + 4

Now, we add/subtract like terms:

3m - 2

Problem 3:

Subtracting two polynomials:

(4m - 5) - (6m - 7 + 2n)

We first start by getting rid of the brackets. Take care of the different signs while doing so:

4m - 5 - 6m + 7 - 2n

Now, we add/subtract like terms:

-2m - 2n + 2

As an additional step, we can take -2 as a common factor from the above expression:

-2(m+n-1)

Hope this helps :)

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6