Which numbers is visible by 3. 65,117,39,195,78,26,312,936,520,260 ,52,104

By using the simple rule to see if the numbers are divisible by three, we can solve this equally. Without actually showing my work, it would be easier if I explained the rule. If you add the digits in the number and the sum is divisible by 3, the number is divisible by three ( the sum of the numbers are usually 6,9,12,15; they’re low numbers).

Numbers divisible
117
39
195
78
312
936

There should only be 1 solution