Apilot approaching a 3000-meter runway finds that the angles of depression of the ends of the runway are 14° and 20°. how far is the plane from the closer end of the runway? round to the nearest tenth place.

  The plane is 6,547 feet from the closer edge of the runway.

This is a trigonometry problem that will involve setting up 2 different triangles. One going to the closer edge of the runway and the other going to the far end of the runway.

The constant between the 2 triangles is the height of the plane. You can solve for this is both triangles and set them equal to each other. 

Do that will give you the equation:

x/tan(70) = (x+3000)/tan(76) where x is the distance to the closer end of the runway. 

If you solve that equation, you will get x = 6547 feet.