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Mathematics, 29.07.2019 23:00 lol1516

The work of a student to solve the equation 3(3x βˆ’ 4) = 8 + 2x + 5 is shown below: step 1. 3(3x βˆ’ 4) = 8 + 2x + 5 step 2. 6x βˆ’ 7 = 13 + 2x step 3. 6x βˆ’ 2x = 13 + 7 step 4. 4x = 20 step 5. x = 5 in which step did the student first make an error and what is the correct step? step 2, 9x βˆ’ 12 = 13 + 2x step 2, 9x βˆ’ 4 = 2(6 + x + 3) step 3, 6x + 2x = 13 + 7 step 3, 6x βˆ’ 2x = 13 βˆ’ 7

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The work of a student to solve the equation 3(3x βˆ’ 4) = 8 + 2x + 5 is shown below: step 1. 3(3x βˆ’ 4...
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