What is the equation of the line that is parallel to the line y = x + 4 and passes through the point (6, 5)? y = x + 3 y = x + 7 y = 3x – 13 y = 3x + 5

The line y=x+4 is given in slope-intercept form (y=mx+b) where m is slope and b is the y-intercept.

Parallel lines have the same slope, so we know the line will have a slope of 1. To find the equation of the new line we can plug the slope and given point into the point-slope equation defined as y-k = m(x-h) given point (h,k).

y-5 = 1(x-6)

Now solve the equation for y.

The answer is: y = x - 1

None of the choices are correct.