If p(q-r)x^2 +q(r-p)x + r(p-q) has equal roots, then, 2/q=? ? a)p+ 1/r c)p+r b) 1/p +r d) 1/p + 1/r

a is the correct

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: