Someone me! 1. displacement vectors of 5 km north, 3 km east, 2 km south, and 3 km west combine to a total displacement of 3 km north. 13 km west. 0 km. 2 km south.

3 km north.
the east and west cancel out and the 5 north being greater than the two south leave you to only have to subtract the 2 south from the 5 north

3 km north  
Just add the vectors together. Consider north to be positive, south to be negative, west to be positive, and east to be negative. Just remember to keep north/south and east/west separate from each other. So let's start with 0 north, 0 west.
 Add 5 km north. So 0 + 5 = 5, giving us 5 north, 0 west.
 Add 3 km east. So 0 - 3 = -3, giving us 5 north, -3 west (or 3 east).
 Add 2 km south. So 5 - 2 = 3, giving us 3 north, -3 west (or 3 east)
 Add 3 km west. So -3 + 3 = 0, giving us 3 north, 0 west 
 We can ignore the 0 west, and as a result we're 3 km north of where we originally started. So the total displacement is "3 km north"

The answer of the above question is

Bi’m pretty sure hope it works