The first quartile of a data set is 23, the median is 30, the third quartile is 33, and an outlier is 6. which of these data values would be represented by a point in a modified box plot? a.33 b.6 c.30 d.23

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation:

hello,

as   long as they add up to 180 its correct.