Acompany has determined that 1% of its widgets are defective. if a customer received 2 widgets, what is the probability that they are both defective? a.)1/1,000 b.)1/10,000 c.)1/100 d.)1/10

 The correct option is (B)

Step-by-step explanation:  Given that a company has determined that 1% of its widgets are defective.

We are to find the probability that both widgets are defective, if a customer received 2 widgets.

Let, A and B denote the events that the first widget is defective and the second widget is defective respectively.

Then, we have

The probability that both the widgets received by the customer are defective is given by

Since both A and B are independent events, so we must have

Thus, the required probability is

Option (B) is CORRECT.

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

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step-by-step explanation: