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Mathematics, 30.07.2019 09:30 josyley78

The work of a student to solve the equation 3(2x βˆ’ 4) = 8 + 2x + 6 is shown below: step 1: 3(2x βˆ’ 4) = 8 + 2x + 6 step 2: 5x βˆ’ 7 = 14 + 2x step 3: 5x βˆ’ 2x = 14 + 7 step 4: 3x = 21 step 5: x = 7 in which step did the student first make an error and what is the correct step? step 2; 6x βˆ’ 12 = 14 + 2x step 2; 6x βˆ’ 7 = 2(6 + x + 4) step 3; 5x βˆ’ 2x = 14 βˆ’ 7 step 3; 5x + 2x = 14 + 7

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