Aschool is building a rectangular soccer field that has a perimeter of 340 yards. the soccer field must be 50 yards longer than its width? a. create a let statement and an equation for the given situation?
b. solve your equation to find the length and width of the field in yards

A. Let
L = length of a rectangular soccer field
W = width of a rectangular soccer field
P = perimeter of a rectangular soccer field
L = W + 50 (the length is longer than the width)

For the equation, the formula for a perimeter of the rectangle is
2L + 2W = P
Since the length and perimeter are given, substitute them as
2(W + 50) + 2W = 340

b. Solving for W,
2(W + 50) + 2W = 340
2W + 100 + 2W = 340
2W + 2W = 340 - 100
4W = 240
(4W)/4 = 240/4
W = 60 yards

Solving for L,
L = 60 + 50 = 110 yards

The rectangular soccer field has the length of 110 yards and the width of 60 yards.

Two because two of one thing is two.