Finish the steps below to write a quadratic function for the parabola shown. use the vertex form, f(x) = a(x – h)2 + k, and substitute in the values for h and k. f(x) = a(x – 5)2 + 3 use another point and substitute in values for x and f(x). solve for a. 5 = a(6 – 5)2 + 3 write the function, using the values for h, k, and a. the function is f(x) = (x – )2 + .

Here we want to write the quadratic function for the parabola shown in vertex form.

We will get the function: f(x) = 2*(x - 5)^2 + 3

So the general function of a parabola with vertex (h, k) and leading coefficient a is:

f(x) = a*(x - h)^2 + k

Here, we know the formula:

f(x) = a*(x - 5)^2 + 3

where:

So the vertex is the point (5, 3), and we only must find the value of a to completely determine the parabola's function

We also know that:

f(6) = 5

So we can solve:

5 = a*(6 - 5)^2 + 3

5 = a*(1)^2 + 3

5 = a + 3

5 - 3 = a = 2

So we just found the value of a, replacing this on the parabola's function we get:

f(x) = 2*(x - 5)^2 + 3

If you want to learn more about parabolas, you can read:

link

binomial distribution

median= 2

range = 7-0 = 7

how to find median?

no. of term=28

median=(28+1)/2=14.5th term

the 14th and 15th term are 2, therefore the median is (2+2)/2 = 2

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)