For this question, we will use our knowledge of finding areas of sectors and triangles to find the area of the pizza crust (the segment). a. find the area of the entire slice of pizza. since the slice of pizza is part of a whole pie, let's think of the pizza as a sector of a circle. calculate the area. be sure to show all of you work. b. find the area of the pizza without the crust. we can use our knowledge of triangles for this step. given that the height of the triangle is 5.5 in. and the base of the triangle is 5 in., calculate the area. show all of you work. c. using the calculations from parts a and b, calculate the area of the pizza crust (or segment). you may refer to lesson 6 for a refresher on how to calculate the area of a segment of a circle. show all of your work.

In tossing one coin 10 times, what are your chances for tossing a head? a tail? 2. in tossing one coin 100 times, what are your chances for tossing a head? a tail? 3. in tossing one coin 200 times, what are your chances for tossing a head? a tail? deviation = ((absolute value of the difference between expected heads and observed heads) + (absolute value of the difference between expected tails and observed tails)) divided by total number of tosses. this value should always be positive. 4. what is the deviation for 10 tosses? 5. what is the deviation for the 100 tosses? 6. what is the deviation for 200 tosses? 7. how does increasing the total number of coin tosses from 10 to 100 affect the deviation? 8. how does increasing the total number of tosses from 100 to 200 affect the deviation? 9. what two important probability principles were established in this exercise? 10. the percent of occurrence is the obtained results divided by the total tosses and multiplied by 100%. toss the coins 100 times and record your results. calculate the percent occurrence for each combination. percent head-head occurrence: percent tail-tail occurrence: percent head-tail occurrence:

What are the solutions to the following equation? |m| = 8.5 the value of m is equal to 8.5 and because each distance from zero is 8.5.

At oaknoll school, 90 out of 270 students on computers. what percent of students at oak knoll school do not own computers? round the nearest tenth of a percent.