Mathematics, 31.07.2019 11:30 zivicion

Rose bought some spinach. she used 3/5 of the spinach on a pan of spinach pie for a party and 3/4 of the remaining spinach for a pan for her family. she used the rest of the spinach to make a salad. what fraction of the spinach did she use ti make the salad? b. if rose used 3 pounds of spinach to make the pan of spinach pie for the party , how many pounds of spinach did rose use to make salad?

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Quantity of spinach that Rose bought: x

Quantity used on the pan of spinach pie for the party: (3/5)x

Remaining spinach: x-(3/5)x=(1-3/5)x=(5/5-3/5)x=[(5-3)/5]x=(2/5)x

Quantity used on a pan for her family: (3/4)(2/5)x=[(3*2)/(4*5)]=(6/20)x
Quantity used on a pan for her family:(3/10)x

Quantity use to make the salad: x-(3/5)x-(3/10)x=(1-3/5-3/10)x
Quantity use to make the salad: [(10*1-2*3-1*3)/10]x=[(10-6-3)/10]x
Quantity use to make the salad: (1/10)x

a. What fraction of the spinach did she use to make the salad?
She used 1/10 of the spinach to make the salad.

b. If Rose used 3 pounds of spinach to make the pan of spinach pie for the party , how many pounds of spinach did Rose use to make salad?

Quantity used on the pan of spinach pie for the party: (3/5)x= 3 pounds
Quantity used to make the salad: (1/10)x=?

We need to find x. Solving for x in the quantity used on the pan of spinach pie for the party:
(3/5)x=3 pounds
(5/3)(3/5)x=(5/3)(3 pounds)
x=15/3 pounds
x= 5 pounds

Quantity of spinach that Rose bought: x= 5 pounds

Now we can find the quantity used to make the salad:
(1/10)x=(1/10)(5 pounds)=(5/10) pounds=(1/2) pound = 0.5 pound

Quantity used to make the salad is 1/2=0.5 pound

Answer from: Quest

(2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

step-by-step explanation:

simplify the following:

x/x^2 + 3 x + 2 - (x (x + 1))/(x + 2)

combine powers. x/x^2 = x^(1 - 2):

x^(1 - 2) + 3 x + 2 - (x (x + 1))/(x + 2)

1 - 2 = -1:

x^(-1) + 3 x + 2 - (x (x + 1))/(x + 2)

put each term in 1/x + 3 x + 2 - (x (x + 1))/(x + 2) over the common denominator x (x + 2): 1/x + 3 x + 2 - (x (x + 1))/(x + 2) = (x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)):

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2))

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)) = ((x + 2) + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2)):

(2 + x + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

3 x^2 (x + 2) = 3 x^3 + 6 x^2:

(2 + x + 3 x^3 + 6 x^2 + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

2 x (x + 2) = 2 x^2 + 4 x:

(2 + x + 6 x^2 + 3 x^3 + 2 x^2 + 4 x - x^2 (x + 1))/(x (x + 2))

-x^2 (x + 1) = -x^2 - x^3:

(-x^2 - x^3 + 3 x^3 + 6 x^2 + 2 x^2 + 4 x + x + 2)/(x (x + 2))

grouping like terms, 3 x^3 - x^3 + 6 x^2 + 2 x^2 - x^2 + 4 x + x + 2 = (3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2:

((3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

3 x^3 - x^3 = 2 x^3:

(2 x^3 + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

6 x^2 + 2 x^2 - x^2 = 7 x^2:

(2 x^3 + 7 x^2 + (x + 4 x) + 2)/(x (x + 2))

x + 4 x = 5 x:

answer: (2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

Answer from: Quest

That. you would have multiple

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