The population of a town increased from 5,600 to 6,300 people. what was the percent of the increase?

To get the percentage, first, we must subtract 5,600 from 6,300.
6,300 - 5,600 = 700
.
Second, we must divide 700 by 5,600.
700 / 5,600 = 0.125
.
Then, move the decimal place two places to the right and add a percent sign (%).
0.125 = 12.5%
.
Therefore, the percent of increase of the population of the town is 12.5%.
:)

X=6300×100/5600=112,5
112,5-100=12,5
The percent of the increase  is 12,5

+1,000)=g7e=mc2-g=7 because if you know algebra you should know g=7 to get your answer

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