Convert the parametic equation x(l)=2-3t and y(t)=4+l into slope intercept form

I guess those 'L' are 't'.

Solve for t in both parametric equations:





Now, you have two expressions for t. The must be equal to each other:



Solve for y in this last equation:



And you've got the slope-intercept form.

Yo could also find from the beginning the slope: it's the quotient of the coefficients of the parameter:



And, then find the intercept by plugging the point (2,4) into the equation:

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12