Describe the end behavior of the function f(x) = 3 − 4x + 6x2 − 5x3.

we are given

we can see that this is polynomial

so, firstly we will find degree and leading coefficients

Degree:

It is the highest exponent of the polynomial

highest exponent is 3

so, degree=3

which is odd

Leading coefficient:

It is the constant term multiplied to highest exponent term

we can see that

constant term is -5

so, leading coefficient is -5

which is negative

End behavior:

degree is odd and leading coefficient is negative

so, it rises to left and falls to right

or we can also write as

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

its an acute right triangle

step-by-step explanation: