Which expression is a difference of squares with a factor of 2x + 5? 4x2 + 10 4x2 – 10 4x2 + 25 4x2 – 25

4x^2 - 25

Justification:

To find wich equation results in a difference of squares with the factor 2x + 5 you have to multiply the same factor 2x + 5 times the difference 2x - 5.

That is because the product of the sum 2x + 5 times the difference 2x - 5 equals the difference of the square of the first term with the square of the second term.

=> (2x + 5) (2x - 5) = (2x)^2 - (5)^2 = 4x^2 - 25.

So, you have found that 4x^2 - 25 is a difference of square that contains the factors. 2x + 5 and 2x - 5.

We have that
case A) 4x2 + 10 > 2[2x2+5]
case B) 4x2 – 10 > 2[2x2-5]
case C) 4x2 + 25 > 2[2x2+25/2]
case D) 4x2 – 25 > (2x+5)*(2x-5) > is the answer

the answer is the case D) 

The percent increase is 25%