Suppose that during the 1990s, the population of a certain country was increasing by 1.7% each year. if the population at the end of 1993 was 5.4 million, what was the population at the end of 1994? a. 91,800 people c. 5,400,000 people b. 5,612,879 people d. 5,491,800 people

5491800 people

Step-by-step explanation:

Population at the end of 1993=5.4 million people=5400000 people

As it is mentioned that the population increases 1.7% each year, so we have to find the 1.7% of 1993’s population and then add it to the original population of 1993 to get the population for 1994.

1.7% of 5400000=5400000*  1.7/100

=9180000/100

=91800

1.7% of 5400000 is 91800. Adding it to the 1993’s population

〖1994〗^' s population=5400000+91800

=5491800 people

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!

step-by-step explanation:

a and d