The sum of the consecutive numbers is 111. what is the smallest of the three numbers?

Answer=36 + 37 + 38 = 111 (36 is the smallest number)

In algebraic form it is x+ x+1 + x+2 = 111 First you minus the 2 and the 1 to give you 108 and then divide that by 3 to give you x (36). That gives you the smallest of the consecutive numbers. Then add on the one on 36 to give 37 and another one to give 38.

answer:   c ?

step-by-step explanation:

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step-by-step explanation: