Find the slope of the line that passes through the points (3, 6) and (5, 3).

find the slope of a line that passes through the points (-3,-1) and (0, 3)

the y - intercept of the line whose equation is 3x-2y=6 is

(3,6)    (5,3)
(x1,y1)(x2,y2)

The slope equation is: y2-y1
                                 
                                  x2-x1

Replace with numbers: 3-6/5-3

Minus 3 and 6 is equal to -3

Minus 5-3 is 2 

So the fraction is -3/2 (no need to divide because you can't simplify it)

So the slope is -3/2

For the equation you have to replace the letters by 0's 

3×0-2y=6
Times 3 and 0
0-2y=6
Now you want to get the y alone, so minus 0 from both sides 
   0-2y=6
  -0      -0

-2y=6

Divide -2y from the 6

-2y=6
 ---
  -2   -2

y=3 

The y intercept is 3 with the slope of -3/2

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