Ancient slingshots were made form straps of leather that cradled a rock until it was released. one would spin the slingshot in a circle, and the initial path of the released rock would be a straight line tangent to the circle at the point of release. the rock will travel the greatest distance if it is release when the angle between the normal to the path and the horizontal is -45 degrees. the center of the circular path is the origin and the radius of the circle measure 1.25 feet. write and equation of the initial path of the rock in standard form.

Solution:

Taking ON as horizontal axis and OP as vertical axis.

Suppose from the , point M stone is released and it travels the greatest distance.  

∠ MON= -45°→→ angle lies in fourth quadrant.

Where, MN represents the path of rock, which is a straight line.

Taking the Horizontal and vertical component of OM,to get the coordinate of point M

The coordinate of point M will be [1.25 cos (-45°), 1.25 sin(-45°)]=

Taking O as center and Coordinates of O as (0,0) and Coordinates of M as () we get the equation of line OM as

y= tan (315°)× x

As general form of equation of line passing through the origin will be,

y= m x, where m is angle made by line with positive direction of x axis.

m= (360-45)°= 315°

→→y=-x

→→  y +  x=0

equation of line perpendicular to OM will be

→→ x -  y + k=0

Since it passes through .

→→

So, equation of initial path of stone will be:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺