The scores of a high school entrance exam are approximately normally distributed with a given mean mc023-1.jpg = 82.4 and standard deviation mc023-2.jpg = 3.3. what percentage of the scores are between 75.8 and 89?

Answer:   95.4%explanation: first we evaluate the z-scores of 75.8 and 89. the z-score is given by the following formula: whereso, the z-scores of 75.8 and 89 are given byif the score is between 75.8 and 89,                                     75.8  ≤ x  ≤ 89    (1)note that  thus, the score is between 75.8 and 89 if and only if the z-score is between -2 and 2. so, the percent of scores that are between 75.8 and 89 is equal to the z-scores that are between -2 and 2. mathematically,note: the percentage of the scores between 75.8 and 89 is equal to the probability that the scores are between 75.8 and 89.hence, 95.4% of the scores are between 75.8 and 89.

It should be c i think.