An eggscellent problem in ginoni’s farm shop, you can buy her freerange hens’ eggs in boxes of 4, 6, 9 or 20. this means, for example, that you can have 21 eggs by buying two boxes of 6 and a box of 9. list the quantities of eggs that are impossible to buy from her shop. ginoni notices that sales of the 4-egg boxes are poor, so discontinues that size. what is now the highest number of eggs that you can’t buy? prove that all larger quantities are possible.

The boxes we have are of 4, 6, 9 or 20.

So obviously we cant make 1,2,3,5,7, 11 eggs. Thus the quantities of eggs that are impossible to buy from Ginoni's shop are 1,2,3,5,7, 11 eggs.

If Ginoni discontinues the size 4 then the highest number of eggs that you can’t buy is 43.

This result is obtained by inspection and by trial and error method.

It can be shown that all larger quantities are possible using the same inspection and trial and error method.

Let us do a small sample:

6 x 4+20=44

9 x 5=45

20+20+6=46

20+9 x 3=47

6 x 8=48

20+20+9=49

6 x 5+20=50

So on and so forth

depending on others is critical to survival. my source is apex!

step-by-step explanation:

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: