Quadrilateral abcd is inscribed in a circle. m∠a is 64°, m∠b is (6x + 4)°, and m∠c is (9x − 1)°. what is m∠d? 64° 82° 90° 98° 116° nextreset

m∠D is 98°    

Step-by-step explanation:

Given quadrilateral ABCD is inscribed in a circle.

m∠A=64°, m∠B=(6x + 4)°, and m∠C=(9x − 1)°.

we have to find the  m∠D.

As, the sum of opposite angles of cyclic quadrilateral  is 180 i.e they are supplementary.

∴ m∠A+m∠C=180°

64°+(9x-1)°=180°

9x+63=180

9x=117  ⇒ x=13

⇒ m∠B=6x+4=6(13)+4=82

Also, m∠B+m∠D=180°

so m∠D=180-82=98°

Hence, m∠D is 98°    

13cm

step-by-step explanation:

(apex)