6x+18=h(3x+9) what value the constant h in the equation shown below will result in a infinite number of solutions

h = 2

Step-by-step explanation:

6x  + 18  =  h (3x + 9)

To get the value of h, we simply need to make h subject of the formula;

To make h subject of the formula, we simply divide both-side of the equation by (3x + 9)

      =    

(On the right hand side of the equation (3x+2) will cancel out (3x+2) leaving us with h)

      =      h

h  =     ----------------(1)

We want to make the numerator and denominator look the same so that  we can cancel out, at the numerator, we can factor out 2 from 6x + 18

i.e 6x + 18 = 2 ( 3x + 9)

So we can  replace 6x + 18    by  2(3x + 9)  in equation (1)

h =

( on the right hand side of the equation, (3x + 9) will cancel out (3x + 9) leaving us with just 2)

h = 2

We can plug in our h =2 in the initial equation

6x +  18   =  2(3x + 9)

6x + 18 = 6x + 18

This equation has an infinite number of solutions.

Therefore the value of constant h in the equation that can make the equation have an infinite number of solutions is 2

its totaly b

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