Find the surface area of the right square pyramid. round your answer to the nearest hundredth.

Area of Pyramid = 192.96 in.²  

Step-by-step explanation:

Given: Square base pyramid.

          side of square = 8 in.

          Height of pyramid = 7 in.

To find: Total Surface Area of Pyramid

Figure is attached.

Side triangles are all equal in area as they equal length of base and height.

Thus,

Total Surface area of pyramid = area of square base + area of 4 equal

                                                     side triangles.

from figure,

In Δ ABC,

using Pythagoras theorem

AC² = AB² + CB²

AC² = 7² + 4²

AC² = 49 + 16

AC² = 65

AC = √65 in.

AC = 8.06 in.

Base of Triangles = 8 in.

Height of triangles = 8.06 in.

                                       = 4 × 8.06

                                       = 32.24 in.²

Area of Square base = side × side

                                  = 8 × 8

                                  = 64 in.²

⇒ Area of Pyramid = Area of Square base + 4 × Area of triangle

                               = 64 + 4 × 32.24

                               = 64 + 128.96

                               = 192.96 in.²

Therefore, Area of Pyramid = 192.96 in.²  

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.