Ascuba diver has a taut rope connecting the dive boat to an anchor on the ocean floor. the rope is 90 feet long and the water is 80 feet deep. to the nearest tenth of a foot, how far is the anchor from a point directly below the boat?

41.2 feet

Step-by-step explanation:

Refer the attached figure .

A scuba diver has a taut rope connecting the dive boat to an anchor on the ocean floor. The rope is 90 feet i.e. AC = 90 feet.

The depth of water i.e. AB  = 80 feet.

We are supposed to find how far is the anchor from a point directly below the boat i.e. BC

So, to find BC we will use Pythagoras theorem :

Thus the anchor is 41.2 feet from a point directly below the boat.

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.